CS601 Assignment 2 Solution Fall 2021


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Question no 1:

Solution:


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Question no 2:

Part a:


Solution:

Low pass signal:

              fhighest =350KHz

So, sampling rate=2* fhighest

                       =2 * 350KHz

                       =700,000 s

Part b:

Solution:

Nb=log2 2048 bits

Quantization 11 bits/sample:

Bit rate= 700,000*11

             =7700 khz



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CS601 Assignment 2 Solution Fall 2021